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300x^2-480x=0
a = 300; b = -480; c = 0;
Δ = b2-4ac
Δ = -4802-4·300·0
Δ = 230400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{230400}=480$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-480)-480}{2*300}=\frac{0}{600} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-480)+480}{2*300}=\frac{960}{600} =1+3/5 $
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